How do I solve this linear equation? y'+2ytan(x)=sin(x) The answer can be found here: y'+2ytan(x)=sin(x) - Wolfram|Alpha But I would be really greatful if someone could explain the steps involved.
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Originally Posted by jobloggs How do I solve this linear equation? y'+2ytan(x)=sin(x) The answer can be found here: y'+2ytan(x)=sin(x) - Wolfram|Alpha But I would be really greatful if someone could explain the steps involved. first thing you need to do is find you integrating factor which will be Next so now integrate that and you get divide by and get
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