How do I solve this linear equation?
y'+2ytan(x)=sin(x)
The answer can be found here: y'+2ytan(x)=sin(x) - Wolfram|Alpha
But I would be really greatful if someone could explain the steps involved.
How do I solve this linear equation?
y'+2ytan(x)=sin(x)
The answer can be found here: y'+2ytan(x)=sin(x) - Wolfram|Alpha
But I would be really greatful if someone could explain the steps involved.