To get from equation 1 to equation 2, you must differentiate the mean pressure function with respect to z:

That's to EQ2.

All they do for EQ3 is just substitute p_0 for P, and since I'm not too familiar with this topic, I'd just go with it.

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- February 25th 2010, 12:40 AM #1

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- February 25th 2010, 08:09 AM #2

- February 25th 2010, 10:17 AM #3

- February 25th 2010, 10:32 AM #4

- February 25th 2010, 12:09 PM #5

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EQ 2 and 3 are only the left side of EQ 1. Further I set the solution of the diff like right side of EQ 1. So g will be back in EQ 4.

Thanks, this helped me further on. (By the way, P is pressure. And the next steps will end up with a function of temperature with respect to z (after substitude with a gas law). z is height from sea level).