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Math Help - how do i solve this IVP: y'=y^2 -4

  1. #1
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    how do i solve this IVP: y'=y^2 -4

    how do i solve this IVP: y'=y^2 -4

    The answer is found here

    http://www.wolframalpha.com/input/?i=y%27%3Dy^2-4

    But I would like to know the processes involved, thanks.
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  2. #2
    MHF Contributor chisigma's Avatar
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    The DE can be written as...

    \frac{dy}{(y+2)\cdot (y-2)}= dx (1)

    ... so that the variables are 'separable' and the solution is found integrating both terms...

    Kind regards

    \chi \sigma
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  3. #3
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    Thank you very much! Much simpler than I thought
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