# Math Help - how do i solve this IVP: y'=y^2 -4

1. ## how do i solve this IVP: y'=y^2 -4

how do i solve this IVP: y'=y^2 -4

http://www.wolframalpha.com/input/?i=y%27%3Dy^2-4

But I would like to know the processes involved, thanks.

2. The DE can be written as...

$\frac{dy}{(y+2)\cdot (y-2)}= dx$ (1)

... so that the variables are 'separable' and the solution is found integrating both terms...

Kind regards

$\chi$ $\sigma$

3. Thank you very much! Much simpler than I thought