how do i solve this IVP: y'=y^2 -4

The answer is found here

http://www.wolframalpha.com/input/?i=y%27%3Dy^2-4

But I would like to know the processes involved, thanks.

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- Feb 24th 2010, 10:29 AMjobloggshow do i solve this IVP: y'=y^2 -4
how do i solve this IVP: y'=y^2 -4

The answer is found here

http://www.wolframalpha.com/input/?i=y%27%3Dy^2-4

But I would like to know the processes involved, thanks. - Feb 24th 2010, 10:46 AMchisigma
The DE can be written as...

$\displaystyle \frac{dy}{(y+2)\cdot (y-2)}= dx$ (1)

... so that the variables are 'separable' and the solution is found integrating both terms...

Kind regards

$\displaystyle \chi$ $\displaystyle \sigma$ - Feb 24th 2010, 11:14 AMjobloggs
Thank you very much! Much simpler than I thought (Rofl)