Originally Posted by

**arbolis** I must solve $\displaystyle y'+t^2y=1$. I don't think it's separable, due to the 1 on the right side of the equation.

So I used the IF method, with no success.

My attempt:

The IF is $\displaystyle e^{\frac{t^3}{3}}$. Multiplying the equation by it and integrating with respect to t, I reach $\displaystyle e^{\frac{t^3}{3}}y=\int e^{\frac{t^3}{3}} dt $.

I didn't know how to solve this integral and tried wolfram alpha, but the result involves the Gamma function and is pretty hard to reach I believe.

So what do I do?

Can I just say that $\displaystyle y=\frac{\int e^{\frac{t^3}{3}} dt}{e^{\frac{t^3}{3}}}$? It's not really under a nice form though. What do you think?