Thread: differential equations

dy/dx - 2y = 4x^2

with y(0) = -1

any help would be appreciated

Originally Posted by bobguy

dy/dx - 2y = 4x^2

with y(0) = -1

any help would be appreciated

This is first order linear, so it is solved using the Integrating Factor.

The integrating factor is

.


Multiply both sides by the integrating factor:







Now evaluate the right hand side using integration by parts (twice).