Hi everybody,

We consider the following differential equation:

$\displaystyle (E) : y''+2y'+2y=-(x+1)e^{-x}+2$

$\displaystyle g(x)=\int_0^{x} te^{-t} dt$ is a solution to this equation E

1)-I must deduct the solutions of the equation (E)

I know that the solutions are:$\displaystyle e^{-2x}(\alpha cos(x)+ \beta sin(x))$

But how to determine $\displaystyle \alpha$ and $\displaystyle \beta$??