find the exact solution of the IVP. y'=2xy, y(0)=2

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Originally Posted by calculuskid1 find the exact solution of the IVP. y'=2xy, y(0)=2 separate variables ... integrate and use the initial condition to find the solution

Originally Posted by calculuskid1 y'=2xy, y(0)=2 This is a very simple separable DE Now tntegrate both sides.

I got that and i got ln y=x^2+c but im not sure what to do there, ln 2=c so then ln y=x^2+ln2 then y=e^(x^2+ln2) can that be simplified?

Originally Posted by calculuskid1 I got that and i got ln y=x^2+c but im not sure what to do there, ln 2=c so then ln y=x^2+ln2 then y=e^(x^2+ln2) can that be simplified?

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