I have this differential equation:

$\displaystyle (y-x) dy/dy=2(y^2-dy/dx)$

any help or answers/suggestion please? highly appreciated! thanks in advance!

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- Feb 21st 2010, 05:06 AMYehiaMessy Differential Equation!?
I have this differential equation:

$\displaystyle (y-x) dy/dy=2(y^2-dy/dx)$

any help or answers/suggestion please? highly appreciated! thanks in advance! - Feb 21st 2010, 05:13 AMTed
- Feb 21st 2010, 05:20 AMYehia
- Feb 21st 2010, 06:09 AMshawsend
Isolate the derivative and then put it into differential form:

$\displaystyle (y-x)y'=2y^2-2y'$

$\displaystyle y'(y-x+2)=2y^2$

$\displaystyle dy(y-x+2)=2y^2 dx$

Now, can you find an integrating factor? - Feb 21st 2010, 11:42 AMYehia