>>cos(x)=c*d2x/dt2
I assume its more like :
cos(x)=c*d^2(x)/dt^2
=> 1/c * cos(x) = d^2(x)/dt^2
why not just integrate twice?
I'm not entirely sure if this belongs in this forum, but it seemed too difficult for the traditional Calculus forums. Is there any way to integrate cos(x)=c*d2x/dt2, where x is a function of time and c is some arbitrary constant. Please and thank you.