Need assistance arriving at this general solution for a particular ODE:

$\displaystyle e^{y^{3}}=csc(x)y^{2}y'$

$\displaystyle => y' = \frac{e^{y^{3}}}{csc(x)y^{2}}$

$\displaystyle \frac{dy}{dx}= \frac{e^{y^{3}}}{csc(x)y^{2}}$

...??

$\displaystyle =>3cos(x)+C = e^{-y^{3}}$

Ty