Results 1 to 2 of 2

Thread: picard's method of iteration

  1. #1
    Junior Member
    Joined
    Oct 2008
    Posts
    69

    picard's method of iteration

    Hey guys, I'm having some trouble with this problem using picard's successive approximations:

    y' = 2e^x - y, y(0) = 1

    I thought the equation to begin the approximations would be:

    y = 1 + integral of 2e^x - y

    but when i make the substitution for y it doesn't work... any suggestions????
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor Danny's Avatar
    Joined
    Dec 2008
    From
    Conway AR
    Posts
    2,311
    Thanks
    4
    Quote Originally Posted by collegestudent321 View Post
    Hey guys, I'm having some trouble with this problem using picard's successive approximations:

    y' = 2e^x - y, y(0) = 1

    I thought the equation to begin the approximations would be:

    y = 1 + integral of 2e^x - y

    but when i make the substitution for y it doesn't work... any suggestions????
    Yeah, you're good to go.

     <br />
y_{n+1}(t) = 1 + \int_0^x 2e^t - y_n(t)\,dt\;\;(1)<br />

    Then start with y_0(t) = 1 and use eqn (1) recursively.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Picard Iteration
    Posted in the Differential Equations Forum
    Replies: 1
    Last Post: May 12th 2011, 07:51 AM
  2. Replies: 3
    Last Post: March 6th 2010, 03:40 AM
  3. Picard's Iteration
    Posted in the Differential Equations Forum
    Replies: 0
    Last Post: November 23rd 2009, 01:41 PM
  4. Help on variational iteration method
    Posted in the Differential Equations Forum
    Replies: 0
    Last Post: September 15th 2009, 10:12 PM
  5. Picard's Iteration
    Posted in the Calculus Forum
    Replies: 3
    Last Post: February 14th 2009, 09:42 AM

Search Tags


/mathhelpforum @mathhelpforum