Hi,

I have the following DE:

$\displaystyle y' + ycos~x = sin2x$

So i have $\displaystyle e^{\int cos~x} = e^{sinx}$

Multiply both sides by this factor and integrate. Gives me.

$\displaystyle ye^{sinx} = \int e^{sinx} \cdot 2sin~x\cdot cos~x$

This is where im stuck, how to i integrate the right hand side?