Clarification of PDE.

**yungman** · February 10th 2010, 03:21 PM

What is the meaning of $\;\;\frac{\partial u}{\partial t}(x,0)$

Is it equal to $\;\;\frac{\partial u(x,t)}{\partial t}\;\;then\;set\;x=0$

or $\;\;\;\frac{\partial u(x,0)}{\partial t}$

**Danny** · February 10th 2010, 03:32 PM

Originally Posted by yungman

What is the meaning of $\;\;\frac{\partial u}{\partial t}(x,0)$

Is it equal to $\;\;\frac{\partial u(x,t)}{\partial t}\;\;then\;set\;x=0$

or $\;\;\;\frac{\partial u(x,0)}{\partial t}$

It means the first. You can't calculate

$\;\;\;\frac{\partial}{\partial t}\left( u(x,0) \right).$

**yungman** · February 10th 2010, 03:35 PM

Thanks

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