Show that the given equation is not exact but becomes exact when multiplied by the given integrating factor. Solve the equation.
, µ
So first,
and
. Thus,
and
So this is inexact.
Then multiplying everything by µ we get
and
. Thus,
and
. So now they are exact
I have chosen to integrate N first since it's a bit easier than M. So integrating N I get
Then I differentiated this with respect to x getting
Then I compared this to M.
. So from this I get
and then
making my final answer
.
But according to my book the final answer is only
. I'm not sure where the
is going. Help please