I need to get this into standard form to do an initial value problem.
$\displaystyle (4-t^2)y'+2ty=3t^2$
My GUESS is that it becomes $\displaystyle y'+2y/4-t=3/4$ but I have the feeling this probably isn't right. Help please!
I need to get this into standard form to do an initial value problem.
$\displaystyle (4-t^2)y'+2ty=3t^2$
My GUESS is that it becomes $\displaystyle y'+2y/4-t=3/4$ but I have the feeling this probably isn't right. Help please!