I need to get this into standard form to do an initial value problem.

$\displaystyle (4-t^2)y'+2ty=3t^2$

My GUESS is that it becomes $\displaystyle y'+2y/4-t=3/4$ but I have the feeling this probably isn't right. Help please!

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- Feb 9th 2010, 01:19 PMsteph3824Just need help getting something into standard form
I need to get this into standard form to do an initial value problem.

$\displaystyle (4-t^2)y'+2ty=3t^2$

My GUESS is that it becomes $\displaystyle y'+2y/4-t=3/4$ but I have the feeling this probably isn't right. Help please! - Feb 9th 2010, 01:21 PMpickslides
$\displaystyle y'+\frac{2t}{4-t^2}y=\frac{3t^2}{4-t^2}$

Now try integrating factor method.