find the general solution for the differential equation: $\displaystyle y' = (x+y)^2$
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Originally Posted by jmedsy find the general solution for the differential equation: $\displaystyle y' = (x+y)^2$ Substitute $\displaystyle v = x + y$. Note that $\displaystyle \frac{dy}{dx} = \frac{dv}{dx} - 1$.
Originally Posted by mr fantastic Substitute $\displaystyle v = x + y$. Note that $\displaystyle \frac{dy}{dx} = \frac{dv}{dx} - 1$. I understand, thanks.
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