finding general solution

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February 8th 2010, 09:51 PM
jmedsy

finding general solution

find the general solution for the differential equation:

$y' = (x+y)^2$
February 8th 2010, 09:56 PM
mr fantastic

Quote:

Originally Posted by jmedsy

find the general solution for the differential equation:

$y' = (x+y)^2$

Substitute $v = x + y$ . Note that $\frac{dy}{dx} = \frac{dv}{dx} - 1$ .
February 8th 2010, 10:22 PM
jmedsy

Quote:

Originally Posted by mr fantastic

Substitute $v = x + y$ . Note that $\frac{dy}{dx} = \frac{dv}{dx} - 1$ .

I understand, thanks.

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