# finding general solution

• Feb 8th 2010, 09:51 PM
jmedsy
finding general solution
find the general solution for the differential equation:

$y' = (x+y)^2$
• Feb 8th 2010, 09:56 PM
mr fantastic
Quote:

Originally Posted by jmedsy
find the general solution for the differential equation:

$y' = (x+y)^2$

Substitute $v = x + y$. Note that $\frac{dy}{dx} = \frac{dv}{dx} - 1$.
• Feb 8th 2010, 10:22 PM
jmedsy
Quote:

Originally Posted by mr fantastic
Substitute $v = x + y$. Note that $\frac{dy}{dx} = \frac{dv}{dx} - 1$.

I understand, thanks.