Solve:

ut + ((x-1)u)x=0,xE(0,1) & t > 0

I want to try the solutionu(x,t) =f(x + ct),but think this might be incorrect, any ideas?

Printable View

- Feb 3rd 2010, 02:46 AMryanhorneAdvection Equation
Solve:

*u*t + ((*x*-1)*u*)x=0,*x*E(0,1) & t > 0

I want to try the solution*u(x,t*) =*f(x + ct),*but think this might be incorrect, any ideas? - Feb 3rd 2010, 02:48 AMryanhorne
By the way ut, means differnatiate u with t, and ((x-1)u) is differentiated by x

- Feb 3rd 2010, 06:15 AMJester
- Feb 5th 2010, 09:58 AMryanhorne
You a Genius! Cheers