hi,

i have a little problem figuring out what to do with this equation:

$\displaystyle y` = \frac{y^2}{cos(y)-2xy}$

i think the way to go is to inverse the differentials and thus get:

$\displaystyle \frac{dx}{dy} = \frac{cos(y)-2xy}{y^2}$

but i don't know how to follow it through... please help...