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Math Help - 1st order diff. eq.

  1. #1
    Junior Member
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    1st order diff. eq.

    hi,

    i have a little problem figuring out what to do with this equation:

    y` = \frac{y^2}{cos(y)-2xy}

    i think the way to go is to inverse the differentials and thus get:

    \frac{dx}{dy} = \frac{cos(y)-2xy}{y^2}

    but i don't know how to follow it through... please help...
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  2. #2
    MHF Contributor Calculus26's Avatar
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    dx/dy + (2/y)x = cos(y)/y^2

    now use the integrating factor of y^2
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  3. #3
    Junior Member
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    thanks.
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