Hi

I got a problem in DE too

I checked all the possible methods that I've learned so far includes Linear, Homogeneous,Bernoulli, and exact equation however none of them worked for me

Please give me just a little hint on this.

Thank you

Results 1 to 15 of 17

- Jan 31st 2010, 02:22 PM #1

- Joined
- Jan 2010
- Posts
- 15

## Help with this DE problem

Hi

I got a problem in DE too

I checked all the possible methods that I've learned so far includes Linear, Homogeneous,Bernoulli, and exact equation however none of them worked for me

Please give me just a little hint on this.

Thank you

- Jan 31st 2010, 03:50 PM #2

- Jan 31st 2010, 03:56 PM #3

- Joined
- Jan 2010
- Posts
- 15

- Jan 31st 2010, 04:29 PM #4

- Jan 31st 2010, 04:48 PM #5

- Joined
- Jan 2010
- Posts
- 15

- Jan 31st 2010, 04:49 PM #6

- Jan 31st 2010, 05:43 PM #7

- Joined
- Jan 2010
- Posts
- 15

- Jan 31st 2010, 05:45 PM #8

- Jan 31st 2010, 05:51 PM #9

- Joined
- Jan 2010
- Posts
- 15

Im not sure what you're asking

an you give me a little explain? ,why is it not negative?

I found the SOLN , and plug back to orginal problem, with both case c=+-2

,looks like both satify the problem.....

I dont really understand...

And what about uniqueness ... ???? I though they said IVP is unique soln, but... I found 2 C's....

- Feb 1st 2010, 08:30 PM #10

- Joined
- Sep 2009
- Posts
- 82

## general solution

Hi, i read over this post i think i know how to find a "general solution" for this probelm. Its actually a specific case for this problem, but it'll help you find an integrating factor in the form . where "a" and "b" are constants.

Get equation in exact form:

Make this fraction =1

By making "a" and "b" appropriot values this should make the fraction 1. Thereby giving you the values of "a" and "b"to fill in the integrating factor .

This should make the equation turn into an "exact differential equation"

Hope this helps!

*Note: I havent tried this for your specific problem, but this is the solution my professor has taught us and has worked for me on other problems.

- Feb 1st 2010, 08:32 PM #11

- Feb 2nd 2010, 04:00 AM #12

- Feb 2nd 2010, 09:36 AM #13

- Joined
- Jan 2010
- Posts
- 15

- Feb 2nd 2010, 09:44 AM #14

- Joined
- Jan 2010
- Posts
- 15

- Feb 2nd 2010, 01:13 PM #15