Solve the Differential Equation

**mattnx** · January 24th 2010, 12:06 AM

Solve the differential equation: $dy/dx = tan[(y-x)/x]+1 + (y/x$ ) for y.

Solve $dy/dx + (6/5)*cos[x]^2 = y^(-2/3)*e^(-x)*cos[2x]$ for y.

The first one I simplified it down to $Ln(x) + c = 1/4(2v - sin[2-2v] - 2)$ where $v = y/x$ I was wondering if there is an easier way to do this.

I have no clue on the second one O.O

**Pulock2009** · January 28th 2010, 08:17 PM

for the second one is -2/3 the exponent of y and -x the exponent of e???/

**mattnx** · January 28th 2010, 10:15 PM

Yeah, idk why they wont let me do exponents.

**CaptainBlack** · January 28th 2010, 11:15 PM

Originally Posted by mattnx

Yeah, idk why they wont let me do exponents.

use curly brackets around exponents, so e^{ab} gives $e^{ab}$

CB

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