# Thread: Solve the Differential Equation

1. ## Solve the Differential Equation

Solve the differential equation: $dy/dx = tan[(y-x)/x]+1 + (y/x$) for y.

Solve $dy/dx + (6/5)*cos[x]^2 = y^(-2/3)*e^(-x)*cos[2x]$ for y.

The first one I simplified it down to $Ln(x) + c = 1/4(2v - sin[2-2v] - 2)$ where $v = y/x$ I was wondering if there is an easier way to do this.

I have no clue on the second one O.O

2. for the second one is -2/3 the exponent of y and -x the exponent of e???/

3. Yeah, idk why they wont let me do exponents.

4. Originally Posted by mattnx
Yeah, idk why they wont let me do exponents.
use curly brackets around exponents, so e^{ab} gives $e^{ab}$

CB