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- January 20th 2010, 02:44 PM #1

- Joined
- Mar 2009
- Posts
- 18

## xyy' = yy' + x(y')^2

Hi everyone,

I need help trying to solve the following:

Mathematica says the solution is but I have no idea how to get there.

I just noticed that the RHS can be written as (xyy')' but made no progress from there.

Any help is appreciated. Thanks!

- January 20th 2010, 03:24 PM #2

- January 20th 2010, 03:57 PM #3

- January 20th 2010, 07:15 PM #4

- January 20th 2010, 07:34 PM #5