1. ## Differentail Equation

dh=[b*(k*e^(2*a*b*t)-1)/(k*e^(2*a*b*t)+1)]*dt,

where a>0 b>0 and k>0 are constants and k#1
I need to find some solution.

2. Originally Posted by Emilly
dh=[b*(k*e^(2*a*b*t)-1)/(k*e^(2*a*b*t)+1)]*dt,

where a>0 b>0 and k>0 are constants and k#1
I need to find some solution.
Off-hand, I'd suggest the substitution $u = e^{2abt}$ and then use partial fractions.