dh=[b*(k*e^(2*a*b*t)-1)/(k*e^(2*a*b*t)+1)]*dt, where a>0 b>0 and k>0 are constants and k#1 I need to find some solution.
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Originally Posted by Emilly dh=[b*(k*e^(2*a*b*t)-1)/(k*e^(2*a*b*t)+1)]*dt, where a>0 b>0 and k>0 are constants and k#1 I need to find some solution. Off-hand, I'd suggest the substitution $\displaystyle u = e^{2abt}$ and then use partial fractions.
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