Find the particular solution that satisfies the initial condition.

= e^(r-s) when condition r(0) = 1

1/e^1= e^0+ C which means C= 1/e

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- Jan 12th 2010, 05:14 PMxterminal01Solving a simple differential equation

Find the particular solution that satisfies the initial condition.

= e^(r-s) when condition r(0) = 1

1/e^1= e^0+ C which means C= 1/e - Jan 12th 2010, 05:19 PMpickslides
- Jan 12th 2010, 05:37 PMxterminal01
- Jan 13th 2010, 03:15 PMxterminal01
- Jan 13th 2010, 03:26 PMpickslides
From

I get

then

using to solve for

- Jan 13th 2010, 07:49 PMxterminal01
- Jan 13th 2010, 07:52 PMpickslides