Find the particular solution that satisfies the initial condition.

= e^(r-s) when condition r(0) = 1

1/e^1= e^0+ C which means C= 1/e

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- January 12th 2010, 06:14 PMxterminal01Solving a simple differential equation

Find the particular solution that satisfies the initial condition.

= e^(r-s) when condition r(0) = 1

1/e^1= e^0+ C which means C= 1/e - January 12th 2010, 06:19 PMpickslides
- January 12th 2010, 06:37 PMxterminal01
- January 13th 2010, 04:15 PMxterminal01
- January 13th 2010, 04:26 PMpickslides
From

I get

then

using to solve for

- January 13th 2010, 08:49 PMxterminal01
- January 13th 2010, 08:52 PMpickslides