Is this correct?
$\displaystyle \frac{dy}{dx} = 3x^2y$
$\displaystyle \frac{1}{y} dy = 3x^2dx$
$\displaystyle \int\frac{1}{y}dy= \int(3x^2dx)$
$\displaystyle \ln|x| = x^3dx + C$
Is this correct?
$\displaystyle \frac{dy}{dx} = 3x^2y$
$\displaystyle \frac{1}{y} dy = 3x^2dx$
$\displaystyle \int\frac{1}{y}dy= \int(3x^2dx)$
$\displaystyle \ln|x| = x^3dx + C$