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Math Help - Please I need

  1. #1
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    Please I need

    Please I need a solution
    Attached Thumbnails Attached Thumbnails Please I need-.jpg  
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by dapore View Post
    Please I need a solution
    The reason you have not received any help is that the wording of your problem is near incomprehensible. Please consider rewording and if the original was in English repost the exact wording.

    CB
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  3. #3
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    There is no predicate in
    "Prove that the integration (D^2+ RD+ S)Y= 0
    especially where y= x if R+ SX= 0"

    Prove the the integeration is what? And it's not clear what "R+ SX= 0" means. Is "X" the same as "x"? If not, what is it? If so, R+ Sx= 0 is true for just one value of x, specifically x= -R/S.

    The second equation can be written as X^2D^2- 3XD+ 3)Y= 0 by multiplying both sides by X^2. And then the change of variable x= ln(t) gives an equation "with constant coefficients" like the first equation.
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  4. #4
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    Prove that the equation

    has a special integration If where
    Then Solve the equation
    Last edited by dapore; December 24th 2009 at 04:37 PM.
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  5. #5
    MHF Contributor
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    Quote Originally Posted by dapore View Post
    Prove that Of the equation



    Special solution where

    Then Solve the equation
    Writing your post bigger will not aid in getting you help. If anything it will probably offend most.
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  6. #6
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    Question has been amended
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  7. #7
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    You are now saying, since "X= Y", that you must prove that R+ YS= 0, which is the same as Y= -R/S, satisfies the equation (D^2+ RD+ S)Y= 0.
    That makes sense now, but is wrong! If you replace Y by the constant function -R/S in that equation, D^2Y and DY are both 0 since Y is a constant and the equation reduces to SY= -R= 0 which is not generally true.

    Perhaps you meant "Show that Y= R+ XS, where X is the independent variable, satisfies (D^2+ RD+ S)Y= 0."
    Now, Dy= D(R+ XS)= S and D^2Y= D^2(R+ XS)= D(S)= 0 so the equation becomes 0+ R(S)+ (R+XS)(S) which is still not 0.

    I still have no idea what you are really asking.
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  8. #8
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    Thank you my friends
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