Find the solution

Printable View

- Dec 20th 2009, 08:37 AMdaporeDifferential equation

Find the solution

- Dec 20th 2009, 08:47 AMHallsofIvy
Because y itself does not appear in that equation, let z= dy/dx so the equation becomes $\displaystyle \frac{dz}{dx}- z^2+ 4= 0$. That's a very simple separable first order equation for z. Since z= dy/dx, integrate to find y.

- Dec 20th 2009, 09:08 AMdapore
I hope to complete the solution and you thanks

- Dec 20th 2009, 09:38 AMDefunkt
$\displaystyle \frac{dz}{dx} = z^2 - 4 = (z-2)(z+2) \Rightarrow \frac{dz}{(z-2)(z+2)} = dx$...

- Dec 21st 2009, 07:26 AMdapore
**You the most beautiful tribute (Clapping)**

- Dec 21st 2009, 09:26 AMAnonymitySquared