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Math Help - Fourier method | eigenfunctions

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    Fourier method | eigenfunctions



    [note: also under discussion in sos math cyberboard]
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    Quote Originally Posted by kingwinner View Post


    [note: also under discussion in sos math cyberboard]
    sin((n+1/2)(-\pi))= -1 = - sin((n+1/2)\pi) and
    (n+1/2)cos((n+1/2)(-\pi))= 0 = - sin((n+1/2)\pi) so sin((n+1/2)x) satisfies both u(-\pi)= -u(\pi) and u_x(-\pi)= -u_x(\pi). Yes, of course, they are eigenfunctions.
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