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Thread: Mass-Spring System

  1. December 18th 2009, 07:32 AM #1
    Apprentice123
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    Mass-Spring System

    Why in the mass-spring system the external force is equal to:
    F_{ext} = F_o cos( \omega t)


    What is each term of the equation?


    Another question:
    The mass-spring system with free vibrations are external force? And with vibration damped?
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  2. December 19th 2009, 04:46 AM #2
    HallsofIvy
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    Quote Originally Posted by Apprentice123 View Post
    Why in the mass-spring system the external force is equal to:
    F_{ext} = F_o cos( \omega t)


    What is each term of the equation?
    mass*acceleration= total force.
    mass*acceleration is m\frac{dv}{dt}= m\frac{d^2x}{dt^2}
    The spring force is -kx and you are given F_{ext} = F_o cos( \omega t) so t he total force is -kx+ F_o cos( \omega t).


    Another question:
    The mass-spring system with free vibrations are external force?
    Sorry, I dont understand this question.

    And with vibration damped?
    Just add a damping term to the equation. Is the damping proportional to x or to v= dx/dt?
    Last edited by mr fantastic; December 19th 2009 at 02:25 PM. Reason: Fixed quote tag
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