Well you forgot to add a constant.I found the integral of 1/u(u-1) du = int 1 dt to be -ln(u)+ln(u-1) = t using partial fractions so:
Then you get:
So just solve for C when u(0)=2.
Find the general solution of:
du/dt = u^2-U
I found the integral of 1/u(u-1) du = int 1 dt to be -ln(u)+ln(u-1) = t using partial fractions so:
u = -1/(e^t-1) but u(0) should = 2 and it would leave -1/(1-1) in this case so undefined
Could anyone tell me where I've gone wrong, thanks