# Thread: dy/dx = y/x - x/y

1. ## dy/dx = y/x - x/y

How do I find

dy/dx = y/x - x/y

2. Originally Posted by georgiahelo
How do I find

dy/dx = y/x - x/y
Substitute $u=y/x$ ( $\implies y=xu$ and $\frac{\mathrm{d}y}{\mathrm{d}x} = x\frac{\mathrm{d}u}{\mathrm{d}x}+u$) and solve for $u$.