1. ## step size function

i'm having problem solving this one....
i'll be really grateful if you help me on this one

2. Uhm... I think it might be $-9-e^{3t}$ in the first box, $-(-9-e^{3t})-1$ in the second, $-(-1)-1$ in the third and $-(-1)+3\cos(-9t)$ in the last one. Not sure though...
If this is for WebWork, you could try these. If you have unlimited tries that is.

3. Originally Posted by boxmailman
i'm having problem solving this one....
i'll be really grateful if you help me on this one
Obviously $f_1(t)=-9-e^{3t}$ goes in the first box, then what goes in the $(n+1)$th box is: $f_{n+1}(t)=-f_n(t)+g_{n+1}(t)$ where $g_n(t)$ is the function in the $n$th part of the function definition, so:

$g_1(t)=)=-9-e^{3t}$

$g_2(t)=-1$

$g_3(t)=-1$

$g_4(t)=3 \cos(-9t)$

CB