i'm having problem solving this one....

i'll be really grateful if you help me on this one

http://img12.imageshack.us/img12/3522/20852977.png

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- Nov 29th 2009, 06:14 PMboxmailmanstep size function
i'm having problem solving this one....

i'll be really grateful if you help me on this one

http://img12.imageshack.us/img12/3522/20852977.png - Nov 29th 2009, 09:13 PMmakarooney
Uhm... I think it might be $\displaystyle -9-e^{3t} $ in the first box, $\displaystyle -(-9-e^{3t})-1 $ in the second,$\displaystyle -(-1)-1 $ in the third and $\displaystyle -(-1)+3\cos(-9t) $ in the last one. Not sure though...

If this is for WebWork, you could try these. If you have unlimited tries that is. - Nov 30th 2009, 12:33 AMCaptainBlack
Obviously $\displaystyle f_1(t)=-9-e^{3t}$ goes in the first box, then what goes in the $\displaystyle (n+1) $th box is: $\displaystyle f_{n+1}(t)=-f_n(t)+g_{n+1}(t)$ where $\displaystyle g_n(t)$ is the function in the $\displaystyle n $th part of the function definition, so:

$\displaystyle g_1(t)=)=-9-e^{3t}$

$\displaystyle g_2(t)=-1$

$\displaystyle g_3(t)=-1$

$\displaystyle g_4(t)=3 \cos(-9t)$

CB