# step size function

• Nov 29th 2009, 06:14 PM
boxmailman
step size function
i'm having problem solving this one....
i'll be really grateful if you help me on this one

http://img12.imageshack.us/img12/3522/20852977.png
• Nov 29th 2009, 09:13 PM
makarooney
Uhm... I think it might be $\displaystyle -9-e^{3t}$ in the first box, $\displaystyle -(-9-e^{3t})-1$ in the second,$\displaystyle -(-1)-1$ in the third and $\displaystyle -(-1)+3\cos(-9t)$ in the last one. Not sure though...
If this is for WebWork, you could try these. If you have unlimited tries that is.
• Nov 30th 2009, 12:33 AM
CaptainBlack
Quote:

Originally Posted by boxmailman
i'm having problem solving this one....
i'll be really grateful if you help me on this one

Obviously $\displaystyle f_1(t)=-9-e^{3t}$ goes in the first box, then what goes in the $\displaystyle (n+1)$th box is: $\displaystyle f_{n+1}(t)=-f_n(t)+g_{n+1}(t)$ where $\displaystyle g_n(t)$ is the function in the $\displaystyle n$th part of the function definition, so:

$\displaystyle g_1(t)=)=-9-e^{3t}$

$\displaystyle g_2(t)=-1$

$\displaystyle g_3(t)=-1$

$\displaystyle g_4(t)=3 \cos(-9t)$

CB