Can you show me how to get the series representation of Gamma(n-3/2+1)?


For example Gamma[(n+3/2+1)=(2n+3)(2n+1)!]/{[2^(2n+2)] n!}


I cannot figure out how to write a series with:

n=0 => Gamma(0-3/2+1)= -2 sqrt(pi)

n=1 => Gamma(1-3/2+1)= sqrt(pi)

n=2 => Gamma(2-3/2+1)= 1/2 sqrt(pi)

n=3 => Gamma(3-3/2+1)= 4/3 sqrt(pi)

Also, I am new here, can you tell me how can I post with math symbols.

I just cannot get a series representation for this gamma function for n=0,1,2....... I have no problem getting the representation for n=1,2,3...... It is the n=0 that gets me!!!!

Thanks

Alan