y"+4y'+29y = <delta>(t-2); y(0) = 0 ; y'(0) = 0

.....

Do laplace of both sides and end up with...

e^-2s * inv laplace [ 1 / (s^2 +4s +29) ]

I tried to comp the square, but it didnt seem to work out quite like i needed...

1 / ( (s+2)^2 + 25)

it looks nice bec 25 is a square too, but i dont know what to do if i did that... i could +4 -4 to top, but i still feel like i am stuck? any help (Hi)