$\displaystyle du/dt = k*d^2u/dx^2$ with initial condition $\displaystyle u(x,0) = x^5$ homework problem that hasnt been covered in class yet.. any help please?
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$\displaystyle u(x,t)=\frac{1}{\sqrt{4k\pi t}}\int_{\mathbb{R}}\exp\left(\frac{-(x-y)^2}{4kt}\right)y^5 dy.$ Enjoy
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