could someone please help me with this one? my answer doesn't match the one in the book so i know i'm doing something wrong but i'm not sure where.
$\displaystyle \frac{dy}{dx}=\sqrt{y}cos^2\sqrt{y}$
i start with the equation above, then i separated the dy/dx
$\displaystyle \frac{1}{\sqrt{y}cos^2\sqrt{y}}dy=dx$
then i integrate both sides and get
$\displaystyle 2ln(cos^2\sqrt{y})=x+C$
that's as far as i get. i'm not sure that i'm integrating the left side right.