Si(x)=integral(sint/tdt) from 0 to x

integrand is 1 at t=0

express the solution y(x) of the initial value problem x^3y'+2x^2y=10sinx, y(0)=0 in terms of Si(x).

What I have done:

y'+2/xy=10x^-3sinx

multiply by x^2

x^2y'+2xy=10x^-2sinx

(x^2y)'=10x^-2sinx

Now I get stuck because I feel like this can't be integrated and I don't think i can just insert Si(x) because I need to account for 10x^-2.