Laplace transform

**harbottle** · November 5th 2009, 02:14 AM

Find the Laplace transform of $t \sin(2t + 5) = G(s)$

So if $F(s) = \mathcal{L}\{\,\sin(2t+5);t \to s\}$

Then $G(s) = -F'(s)$

But $F(s) = \;?$

Any help would be appreciated, thankyou!

**mr fantastic** · November 5th 2009, 03:09 AM

Originally Posted by harbottle

Find the Laplace transform of $t \sin(2t + 5) = G(s)$

So if $F(s) = \mathcal{L}\{\,\sin(2t+5);t \to s\}$

Then $G(s) = F'(s)$

But $F(s) = \;?$

Any help would be appreciated, thankyou!

Note that $\sin (2t + 5) = \sin (2t) \cos (5) + \sin (5) \cos (2t)$ .

**harbottle** · November 5th 2009, 03:18 AM

Thank you!

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