Thread: [SOLVED] Differential equation

Find the function that satisfies the differential equation

and the condition .

So first of all I found integration factor which is
Then I plugged it in for the general solution formula.

which came out to be

y= ∫6dt+C

then it came out to be

+C

then I plugged in the values and got C=1 but all the work done wasn't correct

When you multiply by the integrating factor, the equation becomes

Integrating, you get
so
etc. .