When you multiply by the integrating factor, the equation becomes
Integrating, you get
so
etc. .
Find the function that satisfies the differential equation and the condition .
So first of all I found integration factor which is
Then I plugged it in for the general solution formula.
which came out to be
y= ∫6dt+C
then it came out to be
+C
then I plugged in the values and got C=1 but all the work done wasn't correct