Originally Posted by
Link88 y''-2y'+y=0 ; With Solution y = e^x
So far I got:
let y=f(x)*v = e^xv
y'=e^xv+e^xv'
y''=e^xv+e^xv'+e^xv'+e^xv''
substituting that into y''-2y'+y=0 gets=
e^xv'' and then v''=w' we get
e^xw' not sure where to go from here though : (