y''+6y'+9y = e^(-3x)/X^3
I don't know what to do when b^2-4ac is zero. When I do the Wronskien matrix I can't solve for C1 and C2 cause my y1 and y2 are the same:
x^2 + 6x + 9 = 0
delta = 0
Y(x) = c1e^-3x + c2e^-3x
Can anyone help?
y''+6y'+9y = e^(-3x)/X^3
I don't know what to do when b^2-4ac is zero. When I do the Wronskien matrix I can't solve for C1 and C2 cause my y1 and y2 are the same:
x^2 + 6x + 9 = 0
delta = 0
Y(x) = c1e^-3x + c2e^-3x
Can anyone help?