# Thread: 2nd order differential equation

1. ## 2nd order differential equation

solve for U(x,t), note that U=U(x,t)
Delta(Ut) + 0.1 Delta(Ux) = 0.2 Delta( Uxx)
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Answer: U(x,t) = Exp (1.17712434…x – 0.09t), Exp--> exponential

2. Originally Posted by nirvanakris
solve for U(x,t), note that U=U(x,t)
Delta(Ut) + 0.1 Delta(Ux) = 0.2 Delta( Uxx)
"Delta" is not standard notation. better would be just "U_t+ 0.1U_x= .2U_xx
.
.
.
.
.
Answer: U(x,t) = Exp (1.17712434…x – 0.09t), Exp--> exponential
If you give no initial or boundary conditions, it is impossible to get that! Tell us what the problem really says.

3. Originally Posted by HallsofIvy
"Delta" is not standard notation. better would be just "U_t+ 0.1U_x= .2U_xx
.

If you give no initial or boundary conditions, it is impossible to get that! Tell us what the problem really says.
sory, ive forgot the boudaries...in fact the boudaries are given as :

4. Originally Posted by HallsofIvy
"Delta" is not standard notation. better would be just "U_t+ 0.1U_x= .2U_xx
.

If you give no initial or boundary conditions, it is impossible to get that! Tell us what the problem really says.
sory, ive forgot the boudaries...
so the problem is actually U_t+ 0.1U_x= .02U_xx and the boudaries are given as :