Q) The question is for me to sketch the graph of x(t) for different initial conditions.
dx/dt = sqrt(3) - 2sin(x)
A) i cant see how this is separable variables or integrating factor method.
So do I do: x(t) = sqrt(3)t - 2tsin(x) + C
Saying x = x0 at t=0 just gives me c = x0
Does this look correct?
The question that this equation involves is:
Use a geometric approach and qualitatively analyse the following equations (in each case find fixed points, sketch the vector field and classify stability of each fixed point, sketch the graph of x(t) for different initial conditions).
Does this mean that I actually do have to integrate dx/dt.
On asking my lecturer he said that the hint is in the brackets.
Im so confused