You're correct, the complementary function is
To use Undetermined Coefficients, try
and it will work out.
Sub into the original DE, equate coefficients, and solve for A and B.
Hi,
I have a prblem with a question that I'm working on I've managed to get so far but not sure what my next step should be. I wonder if anyone could point me in the right direction?
I've managed this so far:
QUESTION: Find the general solution of:
d^2 y/ d x^2 - 3dy/dx + 2y = 5 + 6e^7x
Find auxiliary equation: m^2 - 3m + 2
=> (m-1) (m-2) = 0
=> m1 = 1, m2 = 2.
Hence complimentary function is:
Y(x) = Ae^x + Be^2x
Not sure where to go from here. I'm okay with normal inhomogeneous equations but basically..... I hate exponentials lol
Any help would be greatly appreciated! :P
Cheers