Solve:
$\displaystyle \frac{dy}{dx}= \frac{y^3}{1-2xy^2},\ \ y(0)=1$
No idea how to do this, tried various methods and came up with nothing. Any Suggestions on how to attempt this one?
Solve:
$\displaystyle \frac{dy}{dx}= \frac{y^3}{1-2xy^2},\ \ y(0)=1$
No idea how to do this, tried various methods and came up with nothing. Any Suggestions on how to attempt this one?