hi,
Inverse laplace
---(s + 9 )
------------
s^2 + 6s+ 9
-----(s + 3 )
--------------- + .........
(s + 3 )^ 2 + 4
{ e^-3t } * Inverse laplace { s / (s+4) } + .......
I have problem understand this step... how to take away the +3 in the equation ? i know there is a formula in the sheet to give a direct answer given but the example in the book really make my head crack
= e^-3t cos2t + ......
Thank you for any help