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Math Help - spring mass-undamped

  1. #1
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    spring mass-undamped

    A 20-kilogram mass is attached to a spring. If the frequency of simple harmonic motion is 2/pi cycles per second, what is the spring constant k? What is the frequency (in cycles per second) of simple harmonic motion if the original mass is replaced with an 80-kilogram mass?

    would omega=sqrt[k/m]
    frequency=2/pi so omega=4

    what do I do next? or am I totally wrong!?
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  2. #2
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    Quote Originally Posted by latavee View Post
    A 20-kilogram mass is attached to a spring. If the frequency of simple harmonic motion is 2/pi cycles per second, what is the spring constant k? What is the frequency (in cycles per second) of simple harmonic motion if the original mass is replaced with an 80-kilogram mass?

    would omega=sqrt[k/m]
    frequency=2/pi so omega=4

    what do I do next? or am I totally wrong!?
    Write out the equation of the frequency of the spring-mass system in terms of the mass and spring constant:

    f=\frac{1}{2\pi}\sqrt{\frac{k}{m}} Hz

    You are told that when m=20 kg \ \ f=2/\pi Hz so you can solve for the spring constant k.

    Now you have the spring constant so plug that and a mass of 80 kg into the equation for frequency to calculate the new frequency (or just observe that the mass has gone up by a factor of 4 so the frequency goes down by a factor of 2).

    CB
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  3. #3
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    Thank you

    Thanks, this makes sense now!
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